Python Types: Optional Can Mean Mandatory

The article discusses the frequent misuse and misunderstanding of the typing.Optional type in Python programming. It explains that typing.Optional is used to indicate that a variable can be either a specific type or None. It also provides examples of correct type hints that use Optional and suggests different options for handling optional arguments. The article concludes by highlighting the potential misunderstanding of the term “optional” in the context of typing.Optional.

 Python Types: Optional Can Mean Mandatory

PYTHON PROGRAMMING

Learn how to avoid a frequent misuse and misunderstanding of typing.Optional.

According to the Python documentation, typing.Optional is a way to indicate that an object can be None. But is it clear what “optional” means in this context?

When you see the word “optional” in a Python context, what do you think it means? If you see an argument called x with the type Optional[int], what’s your first thought?

There are two possible interpretations:

  1. I don’t have to provide a value for x because it’s optional.
  2. The value of x can be either an integer or None.

If you’re familiar with Python type hinting, you know that option 2 is correct. But for those who are not familiar, option 1 seems more logical. When something is labeled as optional, it means you don’t have to provide it.

This confusion often leads to the misuse of the typing.Optional type. This article aims to clarify this misuse and guide you towards the correct understanding of this type.

The meaning of typing.Optional

There are three equivalent ways to express that a variable can be either a string or None:

  1. x: Union[str, None]
  2. x: Optional[str]
  3. x: str | None

All three convey the same information. The first one (Union[str, None]) is the older approach to type hinting in Python. Optional was introduced as a more concise and straightforward way to express this concept. According to the mypy documentation, “Optional[X] is the preferred shorthand for Union[X, None]”.

In Python 3.10, the | operator was introduced as an alternative way to spell union types. However, this operator is not specifically designed to indicate that a variable can be None.

When choosing between these three versions, consider the Python version you’re using. If you’re using an older version than 3.10, the | operator may not be available. Additionally, using Optional is recommended by mypy and it works for older Python versions.

Here are some examples of correct type hints using Optional:

Examples of type hints utilizing typing.Optional in Python 3.12:

This article focuses on the misuse of the typing.Optional type and how to avoid it. It explains the source of the misuse, how to correct it, and how to understand the typing.Optional type.

The Optional misunderstanding

Consider the following function signature:

from typing import Optional

def foo(s: str, n: Optional[int] = 1) -> list[str]:
    ...

Let’s analyze the type hints in this function signature:

  • s is a required string argument.
  • n is an optional integer argument with a default value of 1.
  • The foo() function returns a list of strings.

Now, what’s wrong with this analysis?

The issue lies with the interpretation of n as an optional integer. While it’s a valid English sentence, it’s not necessarily a valid typing sentence. The correct meaning of Optional[int] is that n can be either an integer or None, not that you don’t have to provide its value.

There are four options to improve the function signature, each representing a different scenario:

  1. Leave the signature as is.
  2. Use Optional and None as the default value.
  3. Don’t use Optional.
  4. Use Optional for n but require its value.

Option 0: Leave as is

from typing import Optional

def foo(s: str, n: Optional[int] = 1) -> list[str]:
    ...

This type hint is technically correct, but its meaning is rarely what you need. It suggests that n is optional because it has a default value, but it can still be None. This option should be used only in very specific circumstances.

Option 1: Use Optional and None as the default value

from typing import Optional

def foo(s: str, n: Optional[int] = None) -> list[str]:
    if n is None:
        ...
    ...

This is the most common scenario when you need None for an integer. The default value of None triggers a specific action. If the user provides an integer, some processing is done. But when n is None, this processing can be switched off. Use an explicit None check when necessary.

Option 2: Don’t use Optional

def foo(s: str, n: int = 1) -> list[str]:
    ...

In this option, n has a default value, but it cannot be None. You don’t have to provide the value of n, but it cannot be None. This is the correct meaning of optional in English, but incorrect in the typing syntax.

Option 3: Use Optional for n but require its value

def foo(s: str, n: Optional[int]) -> list[str]:
    if n is None:
        ...
    ...

Even though n is Optional, it is not optional. You have to provide its value, but it can still be None. Use an explicit None check when necessary.

In conclusion, the typing.Optional type is often misunderstood. It refers to whether a variable can be None, not whether you have to provide its value. It’s important to be aware of this potential misunderstanding and use the correct type hints in your code.

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